A Beam of Light of Wavelength 600 Nm From a Distant Source Falls

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A Beam of Light of Wavelength 600 Nm From a Distant Source Falls

So, for example, we will with you some questions. Let’s start with the first Question.

Q1. A beam of light of wavelength 600 nm from a distance source falls on a slit 1 mm wide and the resultant diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central bright fringe is:

  • 1.2 cm
  • 1.2 mm
  • 2.4 cm
  • 2.4 mm

Right Answer: 2.4 mm

Solution

Correct option is D)

for a dark fringe to form
Ddy​=λ
y=dDλ​=10−32×600×10−9​=1.2mm

The distance between the first dark fringes on either side of the central bright fringe is 2×y=2.4mm
option 2.4mm is correct.

video Sulution by Doubtnut

Q2. A beam of light of wavelength 600 nm from a distant source falls on a single slit 1.0 mm wide and the resultant diffraction pattern is observed on a screen 2m away. What is the distance between the first dark fringe to either side of the central bright fringe:

  • 1.2 cm
  • 1.2 mm
  • 4.4 cm
  • 2.4 mm

Right Answer: 2.4 mm

Solution

Correct option is C)

Condition for obtaining mth order minima is 
asinθ=mλThus for obtaining first diffraction minima,
asinθ=λ

⟹sinθ=10−3m600×10−9m​≈tanθ=Dy​⟹y=1.2 mmThus distance between fringes on either side=2×y=2.4 mm.

video Sulution by Doubtnut

Q3.

light of wavelength 6000 A falls on a slit 0.5 mm wide from a distant source. The distance between two dark bands on each side of the central bright band of the diffraction pattern observed on a screen placed at a distance of 2 m from the slit is:

  • 1.2 cm
  • 1.2 mm
  • 2.4 cm
  • 4.8 mm

Right Answer: 4.8 mm

Solution

Correct option is 4.8

Distance between 2 dark bands on each side of the central bright band
=d2×λ×D​
=0.5×10−32×6000×10−10×2​
=4.8×10−3m
=4.8 mm.

Q4. A beam of light of wavelength 600 nm from a distant source falls on a single slit 1.00 mm wide and the resultant diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central maxima is:

  • 1.2 cm
  • 1.2 mm
  • 2.4 cm
  • 2.4 mm

Right Answer: 2.4 mm

Solution

Correct option is 2.4 mm

Condition for obtaining mth order minima is 
asinθ=mλThus for obtaining first diffraction minima,
asinθ=λ⟹sinθ=10−3m600×10−9m​≈tanθ=Dy​⟹y=1.2 mmThus distance between fringes on either side=2×y=2.4 mm

Conclusion

So, we have shared with you 4 questions for this query. I think we have solved the query on A Beam of Light of Wavelength 600 Nm From a Distant Source Falls. I hope this Post from Sagaya.co.in was helpful for You. If you have confusion sure Ask us in the comment section.

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